914A - Perfect Squares - CodeForces Solution


brute force implementation math *900

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Python Code:

input();print(max(i for i in [*map(int,input().split())] if i<0 or not (abs(i)**.5).is_integer()))

C++ Code:

#include<bits/stdc++.h>
using namespace std;

bool perfect(int x){
     int root=sqrt(x);
     return x==(root*root);
}

int main(){
  int n;
  cin>>n;
  vector<int>a(n);
  for(int i=0;i<n;i++){
     cin>>a[i];                   
  }
  sort(a.begin(),a.end());
  for(int i=n-1;i>=0;i--){
     if(perfect(a[i])==false){
       cout<<a[i];
       return 0;
     }
  }
 return 0;                      
}


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  • 2/12/2022 19:20 - Asia/Saigon

input();print(max(i for i in [*map(int,input().split())] if i<0 or not (abs(i)**.5).is_integer()))


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